Sort an Array Elements in Ascending Order in C++
A Program to write Sort an Array Elements in Ascending Order in C++ is very simple just follow the same concept which is apply in C programming to write this code.
![Images Sort an Array Elements in Ascending Order in C++](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi3cZkJZb5Jt1qhBkMJ0R_JgWI2g4iwJgIbY6kbnp6AFjyXAUdMKkFkT3nyqSn5jPMRLkXCJG5cmbF9PcjiDiaQ8YZzcAgVIusYjI7pENBHMu1bwHchSDkZYDl-21RgiqvjcKKUN8ovgwHz/s400/Sort+an+array+in+ascending+order+in+C%252B%252B.png)
Code:
#include<iostream.h>
#include<conio.h>
using namespace std;
void main()
{
int a[10],i,j,temp;
cout<<"Enter any 10 number:";
for(i=0;i<10;i++)
{
cin>>a[i];
}
for(i=0;i<10;i++)
{
for(j=0;j<10;j++)
{
if(a[i]<a[j])
{
temp = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}
for(i=0;i<10;i++)
cout<<"Elements in Accending Order:"
cout<<a[i]<<endl;
getch();
}
Output:
Enter any 10 number:
10
20
40
90
80
55
43
98
21
Elements in Accending Order:
10
20
21
40
43
55
80
90
98
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